2007-09-27 11:04:09 · 4 answers · asked by Dr D 7 in Science & Mathematics ➔ Mathematics
What's the fastest way to get the FULL set of solutions?
2007-09-27 11:08:51 · update #1
use sin 5x -sin 7x =2 cos 6x sin(-x) = - 2 cos 6x sin x
2007-09-27 11:14:19 · answer #1 · answered by Theta40 7 · 2⤊ 0⤋
Realize that sin 0 = 0 satisfies the equation
So x = n*pi where n= ...-2,-1,0,1,2,....
2007-09-27 18:18:50 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
â sinx – 2*cos6x*sinx =0,
hence x1=k1*pi, x2=(±pi/3 +2k2*pi)/6;
yes, lobosito
2007-09-27 20:28:15 · answer #3 · answered by Anonymous · 1⤊ 0⤋
sin 0 conviently goes to 0.
x = 0
It would be troublesome to use the trig formulas lol.
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sin 2pi, sin 4pi, sin 6pi, sin 8pi, sin 10pi....
sin x = sin (x+2npi)
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Ironduke, it must be 2pi because pi gives you the negative form.
2007-09-27 18:06:46 · answer #4 · answered by UnknownD 6 · 1⤊ 1⤋