How do you get the square root of 320?

Question

Can you explain how you get the asnwer to the square root of 320? The answer is 8√5 , but I do not know how they got to it. Please explain!

Answer 1

√ 320 = √64x√5 = 8√5.
(You can break √320 up into root ractors, like I have done.)

Answer 2

Just keep breaking it down divide it by the highest number you know that can go into it evenly in this case i would choose 5 and 64 which when you multiply it by eachother its 320.


now you know square root of 64 is 8 you bring that out from under the square root and you would leave 5 under cause there isnt an even number that is the square root of 5.

Answer 3

Well.um
10*32=320 so
out of 10----2 and 5
for 32--- 8 and 4
then in 8--2 and4 and for 4--- 2 and 2. Other 4 --- 2 and 2
now how many twos you got 6 of them there are 3 pairs of twos so do 2*2*2=8 then 5 is left from the 10
so it is 8 square root of 5

Answer 4

Break it down:

2 x 160

2 x 2 x 80

2 x 2 x 2 x 40

2 x 2 x 2 x 2 x 20

2 x 2 x 2 x 2 x 2 x 10

2 x 2 x 2 x 2 x 2 x 2 x 5

Now pull out pairs:

3 pairs of 2s with a 5 left over.

You only take one from each pair and multiply them together

2 x 2 x 2 = 8

Now multiply all the unpaired ones and put them under the √ sign. You only have a 5 left so:

8√5
.
.

Answer 5

One property of square roots is that if y=sqrt(x) and x=ab, then y=sqrt(a)*sqrt(b). In this case, if x=320, a=64 and b=5. y= sqrt(64)*sqrt(5). But sqrt(64)=8.

Answer 6

Divide the number in half until you can't divide it anymore \
Exm=320>160>80.....etc