A ski jumper travels down a slope and leaves the ski track moving in the horizontal direction with a speed of 30 m/s. The landing incline falls off with a slope of 28º.
a. How long is the ski jumper air borne?
b. Where does the ski jumper land on the incline?
2007-09-27 09:48:50 · 1 answers · asked by sciguy 1 in Science & Mathematics ➔ Physics
A ski jumper travels down a slope and leaves the ski track moving in the horizontal direction with a speed of 30 m/s. The landing incline falls off with a slope of 28º.
a. How long is the ski jumper air borne?
b. Where does the ski jumper land on the incline?
I got 2.36s for the time and used the equation d = V * t to find out how far down the hill he travelled, although i don't no if thats the answer to a?
2007-09-27 10:53:01 · update #1
sorry i meant i dont no if that would give me the answer to part b, how far down the incline he lands
2007-09-27 10:58:33 · update #2
For every horizontal meter he travels, the distance to the ground increases by tan(28) or about .5317 m. Gravity moves him downwards at s=(1/2)at² (where a is 9.8 m/s²). So....
t*30*tan(28) = 4.9t² when he lands. Solve the equation for t to get his time in the air. And you really should be able to work out how far down the incline he lands (if you paid any attention at -all- in trig.)
Doug
2007-09-27 10:03:52 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋