Help, I just can't do it! I got a ridiculous answer like -8 +/- root 27.5
which is obviously not right!
2007-09-27 09:29:31 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^2 + 32x +119 = 0
x = [-32 +/- sqrt(32^2-4(2)(119))]/(2*2)
x = [-32 +/- sqrt(72)]/4
x = [-32 +/- 6sqrt(2)]/4
x = -8 +/- 1.5sqrt(2)
2007-09-27 09:37:34 · answer #1 · answered by ironduke8159 7 · 1⤊ 0⤋
equation = 2x^2 +32x +119=0
let, roots of equation =x1 & x2
x1= -b + sqrt(d)/2a & x2= -b - sqrt(d)/2a , a iz coeff of x^2
, b iz coeff of x
, c iz coeff of constant
sqrt(d)=sqrt( b^2 -4ac) =sqrt(1024 - 952) =sqrt( 72)
so, sqrt(d) = 2.3.sqrt(2)
so, x1 = -32 + 6sqrt(2)/ 4 = -16 + 3sqrt(2)/ 2
& x2 = -32 -6sqrt(2)/ 4 = -16 - 3sqrt(2)/2
2007-09-27 16:38:22 · answer #2 · answered by aryan v 2 · 0⤊ 0⤋