2007-09-27 08:56:51 · 9 answers · asked by Erin 2 in Science & Mathematics ➔ Mathematics
1 , 2 ,3 , 4 , 6 , 7, 12 , 84
2007-09-30 04:59:54 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Hi Erin -- The easiest way to do this and not miss any is to use the tree method
84
12 - 7
6-2
3-2-2
So, 3-2-2-7
Now that we have the lowest factors - all the combinations will give the answer
1-84
2-42
3-28
4-21
6-14
7-12
and then the next item would be 12-7 (and you can see it's starts to repeat) so you have them all!
Hope that helps.
2007-09-27 09:16:47 · answer #2 · answered by pyz01 7 · 0⤊ 0⤋
The above answers are missing one set: 3 and 28. :)
Your pairs would be: 1 and 84, 2 and 42, 3 and 28, 4 and 21, 6 and 14, and 7 and 12.
2007-09-27 09:06:54 · answer #3 · answered by RustyL71 4 · 0⤊ 1⤋
Factors of 84
1 x 84
2 x 42
3 x 28
4 x 21
6 x 14
7 x 12
- - - - - - - - -s-
2007-09-27 09:23:13 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
1,2,4... All numbers that after been mutiplied by a indigit can get the result 84. Including 84 itself
2007-09-27 09:04:47 · answer #5 · answered by Anonymous · 0⤊ 0⤋
1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, and 82
2007-09-27 09:15:00 · answer #6 · answered by aelt15aelt 2 · 0⤊ 1⤋
Did someone forget 3 and 28?
2007-09-27 09:06:38 · answer #7 · answered by Dave T 4 · 0⤊ 0⤋
1,2,4,6,7,12,14,21,42,84
2007-09-27 09:01:46 · answer #8 · answered by god_of_war 4 · 0⤊ 2⤋
1,2,4,6,7,12,14,21,42,84
2007-09-27 08:59:55 · answer #9 · answered by lolzpwndxasaurusrex111 3 · 2⤊ 1⤋