physics problem?

Question

A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 971 N and 1450 N, respectively. The acceleration of the cable is 0.620 m/s2, upward. What is the tension in the cable (a) below the worker and (b) above the worker?

http://i14.photobucket.com/albums/a314/jenny_8639/physics2.gif

Answer 1

Let
m1- mass of the crate
m2 - mass of the workwerAbove the worker
a - upward acceleration
g - acceelration due to gravity
W=mg

The tention above the worker is
T=(m1 + m2)(g +a) and since m=W/g
T= (W1 + W2) (g + a)/g
T=(971 + 1450) (9.81 + 0.620)/9.81=2510 N



Below the worker
T=(m1)(g +a)
T=(W1)/(g+a)/g=
T=1030N

Answer 2

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