2007-09-27 07:21:44 · 8 answers · asked by astalavista 1 in Science & Mathematics ➔ Mathematics
720
2007-09-27 07:27:42 · answer #1 · answered by jpferrierjr 4 · 1⤊ 2⤋
10 x 9 x 8 = 720
2007-10-01 05:13:40 · answer #2 · answered by Como 7 · 0⤊ 0⤋
'!' mean factorial
10! means you multiply 10 X 9 X 8 X 7... X 1
and
7! means 7 X6 X 5 ... X 1
so, when you have factorials like this, you can look at them as
10 X 9 X 8 X 7!
divided by
7!
now you can cleanly factor out the 7! from the top and bottom and all you have to compute is 10 X 9 X 8.
2007-09-27 07:25:35 · answer #3 · answered by Haley 5 · 2⤊ 0⤋
Make the fractions mistaken 10 x 28 + 9 = 289/10 10 x 7 + 7 = seventy seven/10 seeing that they have the comparable denominator, upload the numerators 366/10 Simplify (divide numerator via denominator) 36 6/10
2017-01-02 18:28:49 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Factorials are not as difficult once you recognize and apply n! = n*(n-1)! or 10! = 10*9! Using that same principal 10! = 10*9*8*7!
so you have 10*9*8*7!/7! = 10*9*8= 720
The neat thing about this concept that it works with even very large numbers such as 52!/50! = 52 *51 = 2652
2007-09-27 07:29:32 · answer #5 · answered by Peter m 5 · 0⤊ 0⤋
10! / 7! = (10*9*8*7!) / 7! = 10*9*8 = 720
2007-09-27 07:33:52 · answer #6 · answered by Xero Sinko 2 · 0⤊ 0⤋
10!/7!=10x9x8x7! / 7! = 10x9x8 = 720
2007-09-27 07:26:49 · answer #7 · answered by `Jelena` 1 · 1⤊ 1⤋
Factorialize both numbers, and divide.
2007-09-27 07:23:40 · answer #8 · answered by Brian L 7 · 1⤊ 1⤋