(C4H10) + (O2) ------> (CO2) + (H2O)
2007-09-27 07:05:58 · 4 answers · asked by natsyy 1 in Science & Mathematics ➔ Chemistry
You need to know how to do this-
1) There is one molecule containing C on either side: C4H10 on the reactant side and CO2 on the product side.
Start by balancing the carbon-
C4H10 + O2 --> 4CO2 + H2O
2) There is one molecule containing H on either side: C4H10 on the reactant side and H2O on the product side.
Continue by balancing the hydrogen-
C4H10 + O2 --> 4CO2 + 5H2O
3) Now the C and the H are balanced, but not the oxygen.
There are 13 oxygen atoms on the product side (8 in 4CO2 and 5 in 5H2O). To get 13 oxygen atoms on the reactant side, you need 6.5 O2 molecule-
C4H10 + 6.5O2 --> 4CO2 + 5H2O
4) Most teachers want only whole numbers for the coefficients of the molecules. If you multiply all of the coefficients by 2, you will convert 6.5 to 13-
2C4H10 + 13O2 --> 8CO2 + 10H2O
The reaction equation is now balanced. Take it step by step and it is not too hard. Practice makes it even easier.
2007-09-27 07:38:03 · answer #1 · answered by skipper 7 · 1⤊ 0⤋
C4H10 + 6.5 O2 = 4 CO2 + 5H2O
2007-09-27 14:16:08 · answer #2 · answered by Yheng Natividad 3 · 0⤊ 0⤋
2.(C4H10) + 13.O2 --------> 8.(CO2) + 10.(H2O)
2007-09-27 14:17:10 · answer #3 · answered by Calculus 5 · 0⤊ 0⤋
2C4H10 + 13O2 ===> 8CO2 + 10H2O
2007-09-27 14:12:53 · answer #4 · answered by steve_geo1 7 · 1⤊ 0⤋