Please help explain this chemistry problem and how to do it!!!?

Question

A stopper was found to have a mass of 5.06g. When placed in a graduated cylinder containing 45.2mL of water, the volume of the stopper was found to be 49.4mL. What is the density of the stopper?

Answer 1

I think you miscopied. The original water was 45.2 mL. When the stopper was added, the water rose to the 49.4-mL mark. The volume of the stopper was thus 49.4 - 45.2 = 4.2 mL.

5.06g/4.2mL = 1.20 g/mL

Answer 2

HAi furikuri405,

It will be 0.1024 g/ml.

(I assume the 45.2mL of water is mentioned only to mislead you. I have taken 49.4mL as the correct volume of the stopper. By the answer we have got, 49.4mL seems appropriate, because the stopper will be much lighter than water whose density is about 1g/ml.)

Answer 3

Okay. Density equals mass divided by volume, or D=m/v. The volume value will be the difference between your volumes before and after the object was added. Your equation should look like this:

D=5.06g/(49.4ml-4.2ml)
D= 5.06g/4.2ml
D=1.20g/ml (rounded to 2 decimal places)

Answer 4

The Volume of the stopper should be 49.4 - 45.2 = 4.2 mL, instead of the 49.4 mL.

D =m/V

m = 5.06 g
V = 49.4 - 45.2 = 4.2 mL = 4.2 cm^3

D = 5.06 g / 4.2 cm^3
=1.20 g/cm^3