What happens when you place sodium ethanoate powder in dilute hydrochloric acid and warm the mixture?
I would also appreciate any equations (or reaction mechanism if applicable)
2007-09-27 06:28:16 · 2 answers · asked by H 1 in Science & Mathematics ➔ Chemistry
CH3COONa(s) + HCl(aq) ===> CH3COOH + NaCl(aq)
You don't even have to warm the mixture. Acetic acid is only slightly ionized, so that drives the reaction (mostly) to the right.
2007-09-27 06:36:55 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
The dehydration of a million-butanol will provide a mixture of butenes, so which you may get a mixture of dibromobutanes. the extra advantageous approach may well be to do the removal to furnish in basic terms a million-butene. this may well be accomplished with an acetate or xanthate pyrolysis, yet that chemistry isn't in all textbooks. If not then convert the alcohol to its chloride with thionyl chloride. in case you cope with a million-chlorobutane with KOtBu, the biggest product would be a million-butene and n-butyl t-butyl ether as a minor element. Bromination of a million-butene will provide a million,2-dibromobutane.
2016-10-20 03:49:31 · answer #2 · answered by ? 4 · 0⤊ 0⤋