(7x+3)/3 < 43 I just need help on how to simplify the left side. I tried multiplying it by 3/1 but that doesn't give me the right answer. Please help! Thanks!
2007-09-27 04:09:45 · 5 answers · asked by ♫ ∫aoli 4 in Science & Mathematics ➔ Mathematics
I think the solving will be this type:
(7x+3)<43*3
=> 7x<129-3
=> x<126/7
=> x<18.
2007-09-27 04:17:47 · answer #1 · answered by Nashid 2 · 0⤊ 0⤋
7x + 3 < 129
7x < 126
x < 18
2007-09-27 14:54:39 · answer #2 · answered by Como 7 · 0⤊ 0⤋
(7x+3)/3 < 43
7x+3 < 129
7x < 126
x < 18
2007-09-27 11:13:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(7x + 3) / 3 < 43
7x + 3 < 129
7x < 126
x < 18
2007-10-01 06:53:22 · answer #4 · answered by Jun Agruda 7 · 2⤊ 0⤋
(7x + 3)/3 < 43
Multiply by 3
(7x+3) < 129
Subtract 3
7x < 126
Divide by 7
x < 18
2007-09-27 11:12:12 · answer #5 · answered by rahidz2003 6 · 0⤊ 0⤋