how do i integrate:
( sin (1/x) ) / x^2 dx
i know i take the substitution of u=1/x becos it says in the question.
:-)
2007-09-27 03:49:20 · 3 answers · asked by hyperpringle 1 in Science & Mathematics ➔ Mathematics
Just tell the teacher the question was a waste of time and you're never going to need to know that in the real world.
I'm an engineer and half the stuff I learned at school and college I've never used !!!
Good luck ;-)
2007-09-27 03:58:21 · answer #1 · answered by Working@home;-) 1 · 0⤊ 0⤋
So do the substitution. You should have no problem doing the integral after that. And you should get cos(1/x) + C as your answer.
Doug
2007-09-27 04:04:10 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
set u=(1/x)
du=-1/x^2 dx
then look at the equation this way sinu(1/x^2)dx which the 1/x^2 dx becomes du.
so you get the integral -sinu du. then do simple integration.
2007-09-27 04:00:04 · answer #3 · answered by shadoyaj 4 · 1⤊ 0⤋