f=9/5C+32. What is the fahrenheit temp that corresponds to each of the following Celsius temps: -10,0,15,100
2007-09-27 03:15:06 · 7 answers · asked by renae c 2 in Science & Mathematics ➔ Mathematics
Plug -10 into the equation:
F = (9/5)(-10) + 32 -->
F = -90/5 + 32 -->
F = -18 + 32 -->
F = 14
Calculate other temps likewise and you get:
C=-10, F=14;
C=0, F=32;
C=15, F=59;
C=100, F=212
2007-09-27 03:24:52 · answer #1 · answered by Anthony P - Greece 2 · 1⤊ 0⤋
F = 9/5 C + 32
For C = -10, F = 9/5 (-10) + 32 = -18 + 32 = + 14 F
For C = 0, F = 9/5 C + 32 = 0 + 32 = + 32 F
For C = 15, F = 9/5 x 15 + 32 = 27 + 32 = 59 F
For C = 100, F = 9/5 x 100 + 32 = 180 + 32 = 212 F
2007-09-27 10:27:54 · answer #2 · answered by Swamy 7 · 1⤊ 0⤋
In Fahrenheit:
= (- 10 * 9/5) + 32
= - 18 + 32
= 14
= 32
= (15 * 9/5) + 32
= 27 + 32
= 59
= (100 * 9/5) + 32
= 180 + 32
= 212
2007-10-01 05:31:10 · answer #3 · answered by Jun Agruda 7 · 2⤊ 0⤋
f=9/5C+32
1) Sub C = -10
f=9/5(-10)+32
f=31.82
2) Sub C = 0
f=9/5(0)+32
f = 32
3) Sub C = 15
f=9/5(15)+32
f= 32.12
4) Sub C = 100
f=9/5(100)+32
f=32.018
2007-09-27 10:25:14 · answer #4 · answered by XxSyNd3rXx 2 · 0⤊ 2⤋
15 C = 59 F
2007-09-27 10:23:46 · answer #5 · answered by andru 2 · 1⤊ 0⤋
-10=14 F
0= 32 F
15=40.3 F
100= 212 F
2007-09-27 10:20:06 · answer #6 · answered by Jen_Ja_Fers 1 · 0⤊ 1⤋
simply plug in each of the celcius temps in for C.
C=-10 f=14
C= 0 f=32
C=15 f=68
C=100 f=212
2007-09-27 10:20:17 · answer #7 · answered by Nilly 3 · 0⤊ 1⤋