A ten volume set of books stands on the shelf. The first five books (1-5) are each 7.4com thick. The last five books (6-10) are each 9.6 com thick. A bookworm starts at the front cover of volume one and eats his way in a straight horizontal line through to the back cover of volume ten. How far does the worm travel
2007-09-26 22:19:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The front cover of each book is next to the back cover of book next to it. So, you only have to sum the widths of books 2 thru 9: 4*7.4 + 4*9.6 = 4*(7.4 + 9.6) = 4*17 = 68
2007-09-26 22:26:18 · answer #1 · answered by Amit Y 5 · 0⤊ 0⤋
You have to know whether the books are placed left to right (1->10) or right to left (10->1)
If the first way, don't include the first and last books.
If the second way, include them all.
2007-09-27 05:31:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
= multiply 7.4cm by 5 books => 37cm/com (i don't know what's this)
= multiply 9.6cm by 5 books => 48cm/com
= add 37 and 48 =>85cm/com - the distance traveled by the worm.
2007-09-27 05:28:20 · answer #3 · answered by ~steffi~ 2 · 0⤊ 0⤋
actually we arrange books in the way that we ppl see their bones? so it's
4*(7.4+9.6)
=4*17
=68
2007-09-27 05:35:11 · answer #4 · answered by Mugen is Strong 7 · 1⤊ 0⤋
(7.4+9.6)*5
+85cm
2007-09-27 05:29:46 · answer #5 · answered by L-UNIT 1 · 0⤊ 1⤋