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2007-09-26 19:14:16 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

Isnt it suppose to be

O -2
S +5
Mn +3

since (SO4) has the charge of -3?

so 4 O is -8 and S is +5 to a total of -3?
Mn will just make it neutral?

2007-09-26 19:35:44 · update #1

4 answers

I think u've mistaken 1 thing.
S has oxidation number +6, and O has -2,
so SO4 has -2.

And Mn has +2 here.

So it is a neutral atom.
But if u give some other reactive reagent, then Mn^2+ can give almost 5e- and will be Mn^7+.

2007-09-26 20:23:57 · answer #1 · answered by Nashid 2 · 0 0

now not specific what acac is, i assume that could be a bidentate ligand that coordinates by using skill of nitrogen atom lone pairs. if so, then vanadium looses 2 electrons to oxygen, so the oxidation state is V(2+)

2016-12-17 11:23:16 · answer #2 · answered by eisenhauer 4 · 0 0

Oxidation state of
Mn: +2
S: +6
O: -2

2007-09-26 19:18:31 · answer #3 · answered by Bananaman 5 · 0 0

Mn = +2
S = +6
O = -2

The whole compound is zero.

2007-09-26 19:17:39 · answer #4 · answered by Gervald F 7 · 0 0

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