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CH3BR
CH3CL
CH3I
CH3F

2007-09-26 17:10:17 · 4 answers · asked by Lonely 2 in Science & Mathematics Chemistry

4 answers

I know that CH3CL and CH3BR are released even without boiling, and are most predominant . CH3I comes in third.
The answer is CH3F.
Here is a website. http://www.nist.gov/srd/PDFfiles/jpcrd607.pdf

2007-09-26 17:28:52 · answer #1 · answered by QuiteNewHere 7 · 0 0

For a series of compounds with similar structure boiling point is in order of molecular weight (size) so the heaviest CH3I has the highest B.Pt, CH3F the lowest.

2007-09-27 00:23:50 · answer #2 · answered by Aurium 6 · 0 0

Boiling point decrease as you go down the group. So CH3F has the lowest Boiling point and CH3I has the highest Boiling point.

2007-09-27 00:21:42 · answer #3 · answered by Madiha A 2 · 0 0

CH3F I would say because it has the most polar/the strongest bond and therefore would take more energy in the form of heat to break.

2007-09-27 00:19:26 · answer #4 · answered by Linnea L 3 · 0 1

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