Calculus - Definite Integral?

1 ⤊

Calculus - Definite Integral?

0
∫ e^(3x) dx
-∞

Thanks for your help!

2007-09-26 16:38:16 · 4 answers · asked by mrbsktbll10234 1 in Science & Mathematics ➔ Mathematics

4 answers

0 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` 0
∫ e^(3x) dx = (1/3)e^(3x) |
-∞ ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` -∞
= (1/3) (1 - 0)
= 1/3

2007-09-26 16:59:56 · answer #1 · answered by vlee1225 6 · 0⤊ 0⤋

1/3

2007-09-26 16:42:50 · answer #2 · answered by 121221 2 · 0⤊ 0⤋

I = â« e^(3x) dx between given limits.
I = (1/3) e^(3x)
I = (1/3) [ e^0 - e^(-â) ]
I = 1 / 3 [1 - 0 ]
I = 1 / 3

2007-09-26 21:06:30 · answer #3 · answered by Como 7 · 1⤊ 0⤋

u=3x
du=3dx

so the integrand becomes
(e^u)/3*du

integrated, it is
(e^u)/3=(e^(3x))/3
and e^0=1 and e to the negative infinity is 0 so the answer is 1

2007-09-26 16:43:23 · answer #4 · answered by Dokta T 2 · 0⤊ 0⤋