3(2+4(3x-2)=3[2+4(3x-2)]
3[2+12x-8]
3[-6+12x]
-18+36x
2007-09-26 17:01:23
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answer #1
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answered by Anonymous
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This is an a x b x c problem where a = 3, b = (2 + 4) and c = (3x - 2). The Law of Associativity applies: a x b x c = a x (b x c) or (a x b) x c or (a x b x c).
First try to get rid of the parentheses.
3(6)(3x - 2)
Multiply the constants:
18(3x - 2)
Multiply using the Law of Distribution:
54x - 36
2007-09-26 23:51:23
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answer #2
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answered by Wile E. 7
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The (2+4) simplifies to 6. So you have 3*6*(3x -2). The 2*6 is obviously just 18, giving you 18(3x -2). Now distribute the 18 using the distributive rule.
2007-09-26 23:41:18
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answer #3
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answered by Anonymous
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This simplifies to 3 * 6 * (3x-2) =
18 * (3x-2) =
54x - 36
2007-09-26 23:42:58
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answer #4
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answered by Shadow 4
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3 (2 + 4)(3x - 2)=
3(6)(3x-2)=
18(3x-2)=
54x-36
2007-09-26 23:42:11
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answer #5
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answered by A Curious Person 2
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FOIL the last two terms:
6x -4+12x-8
Combine like terms:
18x -12
Multiply everything by three:
54x-36
Yeah, would be a lot simpler if you just added 2 and 4, and multiplied, but other problems may have an x and you'll be forced to FOIL.
2007-09-26 23:43:02
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answer #6
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answered by Zack Wilder 3
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3(6)(3x - 2)
18(3x -2)
54x - 36
2007-09-26 23:42:02
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answer #7
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answered by Anonymous
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18 (3x - 2) = 54 x - 36
2007-09-27 04:27:15
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answer #8
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answered by Como 7
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3(2+4)(3x-2)
=3*6(3x-2)
=18(3x-2)
=54x-36
2007-09-26 23:41:38
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answer #9
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answered by alpha 7
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3(2+4)(3x-2)
3(6)(3x-2)
18(3x-2)
54x-36
2007-09-26 23:44:04
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answer #10
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answered by Mike w 2
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