10((x/2)-2)=10((x/5)-1)
5x - 20 = 2x - 10
3x = 10
x = 10/3
2007-09-26 15:57:52
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answer #1
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answered by Anonymous
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x=10/3
2007-09-26 15:59:06
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answer #2
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answered by Y0u 4r3nt l33t y0ur3 4 n00b 2
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First take each side separate and give them a common denominator:
x/2-2 = x/2-4/2=(x-4)/2
x/5-1=x/5-5/5=(x-5)/5
So then you have:
(x-4)/2=(x-5)/5
Then multiply each side by 2 and 5
2*5(x-4)/2=2*5(x-5)/5
cancel out the 2/2 (which equals one) and the 5/5
5(x-4)=2(x-5)
then distribute
5x-20=2x-10
5x-2x-20+20=2x-2x-10+20
3x=10
x=10/3
2007-09-26 15:58:46
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answer #3
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answered by Patty C 3
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(x/2)-2=(x/5)-1
(x-4)/2=(x-5)/5
bring the 2 to the other side, and 5 to the other side,
5(x-4) = 2(x-5)
5x-20 = 2x-10
5x-2x = 20-10
3x=10
x=10/3
2007-09-26 15:58:42
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answer #4
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answered by Anonymous
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5x - 20 = 2x - 10
3x = 10
x = 10 / 3 = 3 1/3
2007-09-26 20:15:18
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answer #5
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answered by Como 7
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10((x/2)-2)=10((x/5)-1)
5x - 20 = 2x - 10
3x = 10
x = 10/3
2007-09-26 16:02:57
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answer #6
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answered by smilingmonkey77 2
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(x/2 -2 = x/5-1) 10
5x-20=2x-10
-2x+20=-2x+20
3x=10
x= 10 / 3
2007-09-26 16:04:40
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answer #7
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answered by Anonymous
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lim x?2 .... [(x² + 5)^(½) + x - 5]/(x - 2) with a view to sparkling up this concern, you may desire to apply L'Hopital's Rule: lim x?c .... f(x)/g(x) = lim x?c .... f(x)'/g(x)' lim x?2 .... [½(2x)(x² + 5)^(-½) + a million]/a million lim x?2 .... [x(x² + 5)^(-½) + a million] lim x?2 .... [(x/?(x² + 5)) + a million] lim x?2 .... [(2/?(2² + 5)) + a million] lim x?2 .... [(2/?(4 + 5)) + a million] lim x?2 .... [(2/?(9)) + a million] lim x?2 .... [(2/3) + (3/3)] = 5/3
2016-11-06 11:47:42
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answer #8
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answered by ? 4
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(x/2) - 2 = (x/5) - 1
2 - 2x = 5 - x
2 = 5 + x
-3 = x
2007-09-26 16:00:49
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answer #9
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answered by The Glorious S.O.B. 7
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(X/2)-2=(X/5)-1
(X/2)-(X/5)=-1+2
(X/2 x 10/10) - (X/5 x 10/10)=1
(5X/10)-(2X/10)=1
3X/10=1
3X=10x1
3X=10
X=10/3
2007-09-26 16:14:59
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answer #10
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answered by Anonymous
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