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Derivative: y = 2 [e^(-x)] * x

Short way; having a lot of trouble with this section.

If it's not too much trouble can you explain how to get the answer?

2007-09-26 15:27:39 · 2 answers · asked by Stacy B 3 in Science & Mathematics Mathematics

2 answers

It's just the product rule (and a tiny bit of chain rule):

y = 2 [e^(-x)] * x
dy/dx = 2 [e^(-x)] d/dx {x} + 2 d/dx {e^(-x)} . x
= 2 e^(-x) . 1 + 2 (e^(-x) . d/dx {-x}) . x
= 2 e^(-x) + 2e^(-x) (-1) . x
= 2 e^(-x) (1 - x).

2007-09-26 15:32:37 · answer #1 · answered by Scarlet Manuka 7 · 0 0

Hi Anon Yes Shy

2016-05-19 21:12:12 · answer #2 · answered by ? 3 · 0 0

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