how to solve? please help
2007-09-26 15:11:39 · 9 answers · asked by anteater42001 1 in Science & Mathematics ➔ Mathematics
2(m+1)+3 = (m-2) 5
2007-09-26 15:13:30 · update #1
2m + 2 + 3 = 5m - 10
15 = 3m
m = 5
2007-09-29 07:56:16 · answer #1 · answered by Como 7 · 1⤊ 0⤋
you distribute first
2m + 2 + 3 = 5m - 10
2m + 5 = 5m -10
Get like terms on each side of the = sign
2m-2m + 5+10 = 5m-2m -10 +10
divide each side by 3 to get the m alone.
15 = 3m
5 = m
hope this helps
2007-09-26 15:18:03 · answer #2 · answered by c_greiff 3 · 0⤊ 0⤋
2(m+1)+3=(m-2)5
2*m=2m, 2*1=2
2m+2+3=(m-2)5
5*m=5m, 5*2=10
2m+2+3=5m-10
then add: -2 and -3 and-5m to both parts
-2+-3+-5m+2m+2+3=-2+-3+-5m+5m-10
then cross out the same values
5m+2m=-2+-3+10
now add
7m=5
now divide both by first part answer
7m/7m=1=5/7=0.714285 w/ the little line on top of 285 to show its a repeating num
m=0.714285
i am the only one correct because you cannot add two different values togethor. for ex can you add two bannanas and a cookie. no, if yes what would it be 3 bankies see what i am saying
2007-09-26 15:30:26 · answer #3 · answered by Muslim Worker 2 · 0⤊ 1⤋
2m +2+3=5m-10
10+2+3= 5m- 2m
15= 3m
15/3=m
m=5
2007-09-26 15:15:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2(m+1)+3=(m-2)5
2m+2+3 = 5m-10
10+2+3 = 5m-2m
15 = 3m
m = 5
2007-09-26 15:14:55 · answer #5 · answered by ^^' 2 · 0⤊ 0⤋
2m+2+3 = 5m - 10, then you get 2m + 5 = 5m - 10, then you bring m's on one side, 5m-2m = 5 + 10 , therefore 3m = 15 so m=5
2007-09-26 15:15:55 · answer #6 · answered by Neil Dave 2 · 0⤊ 0⤋
2(m+1)+3=(m-2)5
2m + 2 + 3 = 5m - 10
2m - 5m = -10 -2 -3
-3m = -15
m = 5
2007-09-26 15:14:22 · answer #7 · answered by Mock Turtle 6 · 0⤊ 0⤋
first factor so
2m+2+3=5m-10
then you solve
so 15=3m
and answer is m = 5
2007-09-26 15:14:50 · answer #8 · answered by Anonymous · 0⤊ 1⤋
2m+2+3=5m-10
-3m+5=-10
-3m=-15
m=5
2007-09-26 15:18:38 · answer #9 · answered by mi nombre 4 · 0⤊ 1⤋