Transformations on trig graphs?

Question

Ok, this is driving me crazy. We have the equation y = -2tan(x+(pi/4))

So, the asymptotes aren't stretched or anything, some are still like pi/2 and -pi/2, right?

Assuming I've got that right

The pi/4 shifts the asymptotes to the right, correct? But then what are they? (pi/2)+(pi/4)? Which for some reason I can't work out....3pi/4? Gah. Help, please?

Yes, this is homework, but I'm not begging for an answer, I'm just severely confused and would rather ask someone with enough time to be on here than my already-stressed friends.

Answer 1

Gaaak! I think you have things mixed up a little. If you have tan (x+a) where a is a positive constant, whatever the tan value is for (x+a) is plotted at x.
Thus, one cycle of the tan function will extend from -3pi/4 to pi/4, since the normal cycle is from -pi/2 to pi/2. IOW, the shift is the the LEFT.