An object is being acted upon by three forces and moves with a constant velocity. One force is 60N along the x-axis, the second is 75N along a direction making a counterclockwise angle of 150 degrees with the x-axis. What is the direction (in degrees) of the third force, measured counterclockwise from the x-axis?
2007-09-26 14:31:52 · 2 answers · asked by purplehaze_2005 1 in Science & Mathematics ➔ Physics
Since the particle is not accelerating the sum of the forces must be zero. Let q = 150 deg angle, F1 = 60 N along x, F2 = 75 N in the direction q and F3 and u be the force and angle respectively, we need to find.
In x: F1 +F2*cos(180 -q) = F3x = x component of F3
In y: F2*sin(180-q) = F3y
F3x = 60 -75*sqrt(3)/2 = -4.95 N
F3y = 37.5 N
u = arctan(F3y/F3x) = 187.53 deg
2007-09-26 14:45:11 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋
The complete gravitational drive is solely identical to the sum of either one of the gravitational forces of the opposite 2, making definite you recall the path of the drive. This path will outcomes in a 'bad' drive or a 'optimistic' drive, wherein each and every might act within the reverse path of the opposite and can (in part) cancel. From the vector elements you're given the space among gadgets and in addition the path from one to yet another and consequently the path of the drive. Since they're all in a instantly line you do not have to fear approximately angles, simply the signal. Good good fortune.
2016-09-05 09:06:38 · answer #2 · answered by ? 4 · 0⤊ 0⤋