4x^2-9
2007-09-26 13:41:45 · 7 answers · asked by jfourline6 1 in Science & Mathematics ➔ Mathematics
(2x+3)(2x-3)
2007-09-26 13:44:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(2x +3)(2x-3)
this is a perfect square because 9 is a square number and since there isnt an x term then it must be +3 and -3. then just make the 4x^2 work so 2x*2x =4x^2. its like a puzzle
2007-09-26 20:46:04 · answer #2 · answered by B-Mar 3 · 0⤊ 0⤋
Okay, I just learned this, so I'll be able to help.
The form for factoring is Ax^2+Bx+C, you got that? The factors of A(times)C need to have a sum of B. Your B right here is 0, because you don't have a Bx in the equation. So, factor AxC. Your C is -36, and -36 has many factors:
1x-36
-1x36
2x-18
-2x18
3x-12
-3x12
4x-9
-4x9
6x-6
That's all your factors of -36, so far. Because 6and -6 cancel each other out, that is the sum of B.
And here's wher Grouping comes in. Split the polynomial up.
4(x^2)(-6x) (6x)(-9) Divide by GCF.
--------------
2x
2x(-3)
Do the same on the other side. Your outcome sohuld be the same on both sides.
6x(-9)
-------
3
2x(-3)
4(2x-3)(2x+3) is your answer.
2007-09-26 21:04:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
This is called difference of two squares.
4x^2 can be expressed as (2x)^2 while 9 can be expressed as 3^2.
The answer would be:
(2x + 3)(2x - 3)
2007-09-26 20:44:23 · answer #4 · answered by Patrick P 2 · 0⤊ 0⤋
4x² - 9
(2x + 3)(2x - 3)
2007-09-26 20:44:50 · answer #5 · answered by Marvin 4 · 0⤊ 0⤋
(2x-3)(2x+3)
2007-09-26 20:57:05 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(2x+3)(2x-3)
2007-09-26 20:44:38 · answer #7 · answered by MamaWomack 2 · 0⤊ 0⤋