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If the derivatives are *exactly* zero, @ zero, then it's not discontinuous. If the derivative is indeterminant, but d/dx x+ and d/dx x- are 0 would be something like the heaviside function of x.

2007-09-26 12:53:49 · answer #1 · answered by supastremph 6 · 1 0

An example here:
http://www.mathreference.com/ca-mv,part.html

2007-09-26 14:58:07 · answer #2 · answered by Theta40 7 · 0 0

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