is 2^x odd even or neither?
2007-09-26 12:38:14 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
f(x) = 2^x is neither an odd or an even function, since 2^x ≠ 2^(-x), and 2^x ≠ - 2^(-x)
x is a variable, not a constant.
2007-09-26 12:43:46 · answer #1 · answered by sahsjing 7 · 0⤊ 1⤋
Since 2^x is neither -2^(-x) or 2^(-x) GENERALLY, then it is neither an even or odd function.
2007-09-26 19:44:55 · answer #2 · answered by supastremph 6 · 0⤊ 1⤋
It all depends on what x is.
If x = 0, then 2^x = 1 <== odd
if x = 0.5, then 2^x = 1.414213562 <== neither
if x = 1, then 2^x = 2 <== even
2007-09-26 19:41:37 · answer #3 · answered by morningfoxnorth 6 · 1⤊ 1⤋
If i interpret your question correctly, you meant odd/even functions.
Use the definition:
Even: f(x) = f(-x)
odd: f(x)= -f(-x)
The result should be neither. Try it out
2007-09-26 19:45:14 · answer #4 · answered by W 3 · 0⤊ 1⤋
Neither. It doesn't have symmetry about the y-axis (even) and it doesn't have symmetry about the origin (odd) either if graphed.
2007-09-26 19:47:32 · answer #5 · answered by fishsteak 1 · 0⤊ 0⤋
even
2007-09-26 19:40:53 · answer #6 · answered by prprpls 4 · 0⤊ 0⤋