does this reduce to 1 + i
2007-09-26 12:05:59 · 6 answers · asked by Jake L 3 in Science & Mathematics ➔ Mathematics
complex number here
2007-09-26 12:46:16 · update #1
yes it does, just like you think.
1+i
2007-09-26 12:14:05 · answer #1 · answered by erikoo7 3 · 0⤊ 0⤋
It is called "distribution"
the entire bracket is multiplied by 1/2, therefore every term in the bracket gets multiplied by 1/2.
(2 + 2i)/2 = (1/2)(2 + 2i)
= (1/2)*2 + (1/2)*2i
=1 + i
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general rule:
k(a+b) = ka + kb
2007-09-26 19:17:05 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋
because of the brackets it is the same as 2/2 + 2i/2 so yes you are correct;
1+i
2007-09-26 19:18:42 · answer #3 · answered by David F 5 · 0⤊ 0⤋
Yes
2007-09-26 19:14:21 · answer #4 · answered by Nicky 4 · 0⤊ 0⤋
actually this problem reduces to just i, the 2 in the denominator cancels out both 2's in the numerator
2007-09-26 19:14:11 · answer #5 · answered by Christine H 1 · 0⤊ 1⤋
yes, (1+i) is correct
2007-09-26 19:14:17 · answer #6 · answered by Josh M 3 · 0⤊ 0⤋