63,279 by 9
27,350 by 5
77,922 by 6
2007-09-26 11:46:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You just need to remember the rules for divisibility by 9, 5 and 6. The answer is yes in all cases.
PROBLEM 1:
A number is divisible by 9 if its digits add up to a multiple of 9.
6+3+2+7+9 = 27 (which is a multiple of 9)
63,279 *is* a multiple of 9.
PROBLEM 2:
A number is divisible by 5 if it ends in 0 or 5
27,350 ends in 0
27,350 *is* a multiple of 5.
PROBLEM 3:
A number is divisible by 6 if it is even (ends in 0, 2, 4, 6 or 8) and is also a multiple of 3. Here you have to check two things.
77,922 ends in 2 (even)
A number is a multiple of 3 if its digits add to 3.
7+7+9+2+2 = 27 (a multiple of 3)
So 77,922 is a multiple of 6.
To confirm you have it, tell me:
Is 36,187 a multiple of 9?
Is 52,115 a multiple of 5?
Is 42,324 a multiple of 6?
Is 12,351 a multiple of 6?
is 15,236 a multiple of 6?
Answer:
YYYNN
2007-09-26 11:50:18 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
Of course, they are all divisible, but did you mean divisible, with no remainder? If so, then plug them into your calculate and if there's no number right of the decimal point (or the decimal point is missing) then it divided evenly. This one will divide evenly: 4 / 2 = 2, and this one will not 1/3 = 0.333333
2007-09-26 18:55:10 · answer #2 · answered by Level 7 is Best 7 · 0⤊ 0⤋
Yes there all divisible
2007-09-26 18:49:04 · answer #3 · answered by Name goes here 3 · 0⤊ 0⤋
yes all of them are. Does that help or do you need further explanation?
2007-09-26 18:50:10 · answer #4 · answered by erikoo7 3 · 0⤊ 0⤋
yes all of them
2007-09-26 18:51:49 · answer #5 · answered by se 1 · 0⤊ 0⤋