Physics voltage question?

Question

Please help! I can't figure this one out.

The gap between electrodes in a spark plug is 0.045cm . To produce an electric spark in a gasoline-air mixture, an electric field of 2.2 X 10^6 V/m must be achieved. On starting a car, what is the magnitude of the minimum voltage difference that must be supplied by the ignition circuit? Answer in units of V.

Answer 1

2,200,000V/m x (0.045cm)(1m/100cm) = 990 volts

Answer 2

2.2 x 10^6 V/m * .00045 m = 990 V

Doug