math question?

Question

what is the derivative of the [Square root of (3t)] - t^2


thanks in advance! :]

Answer 1

Rewrite the equation as:

(3t)^0.5 - t^2 =

Sqrt(3) * t^0.5 - t^2

Now you have everything in exponents -- so you can use the rule that dy/dt (x^n) = n*x^(n-1)

This gives you a derivative of:

Sqrt(3) * (0.5) * t^(-0.5) -2t

Answer 2

sqrt(3)/(2*sqrt(t)) -2t