How do I seperate this mixture of Sodium chloride, Benzoic acid, and silver bromide?

Question

NaCl is soluble in hot and cold water.
C6H5COOH is soluble in hot water but not cold water.
AgBr is insoluble in water.

How do I seperate this mixture of these three solids?

Answer 1

1) add water - NaCl dissolves in the H2O

2) filter off the benzoic acid and AgBr

3) add the benzoic acid and AgBr to water and heat to boiling - filter while boiling - this will separate the AgBr

4) The benzoic acid can be recovered from the second fitrate (cool it, and filter)

5) The AgBr can be recovered from the second filtration

6) The NaCl can be recovered from the first filtrate (evaporate it).

Answer 2

Add water. Add sodium bicarbonate (baking soda) Shake up the whole mass and filter through coffee-machine filter paper. The sodium chloride and sodium benzoate are soluble in weater and they pass through the filter. Silver bromide is water-insoluble, and it does not. Collect silver bromide on thge filter paper. To the water solution filtrate, add hydrochloric aciud until the solution is red to litmus. Shake up the whole mess with diethyl ether. Separate the ether layer from the water layer in a separatory funnel. Evaporate the ether to get the benzoic acid. Evaporate the water layer to get the sodium chloride.

Answer 3

GO to Taco Bell and get a Nacho Bell Grande