please give details on how to solve for the answer.
2007-09-26 09:53:32 · 4 answers · asked by Doubledog 1 in Science & Mathematics ➔ Mathematics
neglecting air resistance
vo = initial velocity =0
g=32.2 ft/s^2
s =distance =72 ft
s=0.5gt^2 +vot
t= sqrt(2s/g)
t=2.11s
2007-09-26 10:03:55 · answer #1 · answered by xandyone 5 · 0⤊ 0⤋
Unless you're talking about "in a vacuum", it totally depends on the density/air resistance of the object. A piece of lead is going to fall much faster than a beach ball.
2007-09-26 17:03:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If it is at 'REST' how can it drop - 'Movement'????
However if it starting from rest then:-
using the kinematic eq'n.
s = ut + 0.5at^2
s = distance moved (72ft) = (21.9456m)
u = initial velocity (0 ms^-1)
t = time taken
a = acceleration (due to gravity = 9.8 ms^-2)
.Substituting the values in to the eq'n
21.9456m = (0x t) + (0.5 x 9.8ms^-2 x t^2)
21.9456 = 0 + 4.9t^2
21.9456 = 4.9t^2
t^2 = 21.9456/4.9
t^2 = 4.478693878
t = sq rt(4.478693878)
t = 2,116292484 seconds.
t ~ 2 secs.
2007-09-26 17:14:54 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
Is this on Earth? Do you have to calculate air resistance?
2007-09-26 17:02:58 · answer #4 · answered by Level 7 is Best 7 · 0⤊ 0⤋