(x/x-2)-(x+1/x)=8/x^2-2x?

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2007-09-26 09:30:28 · 4 answers · asked by abraymond5 1 in Science & Mathematics ➔ Mathematics

Multiply each term by x(x-2),
x^2 - (x+1)(x-2) = 8
Cancel the x^2 terms,
x + 2 = 8
x = 6

2007-09-26 09:38:22 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

x / (x - 2) - (x + 1) / x = 8 / (x)(x - 2)
x Â² - (x + 1)(x - 2) = 8
x Â² - ( x Â² - x - 2 ) = 8
x + 2 = 8
x = 6

2007-09-30 13:54:35 · answer #2 · answered by Como 7 · 0⤊ 0⤋

(x^2-2x)*[(x/x-2)-(x+1/x)=8/x^2-2x]
x^2-(x^2 -x-2) =8
x+2=8
x=6

2007-09-26 16:38:11 · answer #3 · answered by xandyone 5 · 0⤊ 0⤋

You really need to re-write this using properly the parentheses in the right places

2007-09-26 16:35:30 · answer #4 · answered by Xero Sinko 2 · 0⤊ 1⤋