Perimeter and Area question?

Question

Ok I am trying to figure out this question about perimeter and area but I need some help.Here is one that I dont get.

*Area of rectangle=42 in sq, width = 3 in.,length =________

Can you please explain to me how to get this?

Answer 1

Area = length x width

42 =length x 3
42/3 = length
Make sense?
So the length is 14inches.

Answer 2

the area formula is ,
area= length times width
since you have the are and the width,
you plug them into the equation and put in a variable for the length ( i am using L)
42 sq. in = 3 in (L)
you then want to isolate the variable so since 3 is being multiplied by L you divide by 3 to get rid of it. so the it is 42 divided by 3 on the other side. you then get 14 in, so L= 14, the length equals 14 inches.

hope that helps :)

Answer 3

A = LW

So 42 = 3L

L = 42/3 = 14

Answer 4

Area of a rectangle is width times length. In a formula, it looks like this:

A = L * W

You know that A is 42
You know that W is 3

So your equation is:

42 = L * 3

Then you just solve for L by dividing both sides by 3

42/3 = L
14 = L

Answer 5

Area Formula for a rectangle

A = L x W

42 = L3

Divide both sides of the equation by 3

42 / 3 = L3 / 3

42/3 = L

14 = L

- - - - -

The Length is 14 inches

- - - - - -s-

Answer 6

Area = L*W

So substitute
42 = L*3 ; divide both side by 3

14 = L

Check you answer
42 = (14)*3 ??
42 = 42 YES!
Make sense? Hope this helps.

Answer 7

A=l multiplied by w. (l= lenght) (w= width)
42=3 multiplied by ?.
42 divided by 3
14

Answer 8

SO I think you will take 42/3 =14
so length= 14 in.

Answer 9

14, EdIT-you devide 42 by 3 =14, 3x 14=42,Proof.