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A jet plane is flying at a constant altitude. At time t1 = 0 it has
components of velocity v{x} = 88 m/s, v{y} = 111 m/s.
At time t2 = 29.0 s the components are v{x} = 175 m/s, v{y} = 45 m/s.

For this time interval calculate the average acceleration.
Give your answer as a pair of components separated by a comma. For example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. Express your answer using two significant figures.

Find the magnitude of the average acceleration.

Find the direction of the average acceleration (let the direction be the angle that the vector makes with the +x-axis, measured counterclockwise).

2007-09-26 08:04:37 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

v2-v1= 87 i -66 j ( i,j unit vectors along x and y axis)
average acceleration = 1/29 (87i-66j) =3i-2.28j = (3,-2.28)
magnitude = sqrt(9+2.28^2)= 3.77m/s^2
tan@= -2.28/3
so @=322.82 degrees

2007-09-26 08:40:12 · answer #1 · answered by santmann2002 7 · 0 0

Acceleration is the change in velocity divided by the change in time. Calculate the acceleration along each of the axis and there's your answer.

Doug

2007-09-26 08:14:10 · answer #2 · answered by doug_donaghue 7 · 0 0

The airplane`s directional heading could be such that the west component to the airplane`s velocity equals precisely 20.4 mph so as that it cancels the outcomes the 20.4 mph wind has on the path of the airplane. to try this the airplane could be directed at an attitude to the north west in case you want the airplane to shuttle due north. the perfect attitude required for the airplane to shuttle due north could be calculated as follows; Use east as reference 0 levels. airplane`s course attitude = arc cos -20.4/2 hundred = ninety 5.80 5 levels (north west)

2016-10-20 01:32:52 · answer #3 · answered by ? 4 · 0 0

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