A rhinoceros is at the origin of coordinates at time t1=0. For the time interval from t1 to t2 = 12.5 s, the rhino's average velocity has x-component -3.5 m/s and y-component 4.9 m/s.
at time t2= 12.5 s what is the x-coordinate of the rhino?
At time t2= 12.5 s what is the y-coordinate of the rhino?
How far is the rhino from the origin?
2007-09-26 08:02:20 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-3.5 x 12.5 = -43.75 (X-Coord)
4.9 x 12.5 = 61.25 (Y-Coord)
Distance from the origin = sqrt(-43.75^2 + 61.25^2) = 75.3m (3sf)
2007-09-26 08:09:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Multiply each of the rhinos x and y velocity components by 12.5 seconds to get the x and y distances travelled (the (x, y) coordinates of the rhino). Then it's just Pythagorean Theorem to get the distance from the origin.
Doug
2007-09-26 08:09:08 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋