Physics Question?

Question

A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 8420 N/C. The mass of the water drop is 3.10 10-9 kg.
(a) Is the excess charge on the water drop positive or negative?
(o) positive
(_) negative

Why?

(b) How many excess electrons or protons reside on the drop?

Answer 1

(a) Positive
electrons with negative charge would move against the direction of e-field, which is starting from a positive charge and ending into a negative charge.
(b) e = 1.60×10^(-19) C
n = 3.10x10^(-9)*9.81/(8420*1.60×10^(-19))
= 2.26x10^7
(is this ever possible?)