Here's the problem....
A speed skater moving across frictionless ice at 8.40 m/s hits a 4.80-m-wide patch of rough ice. She slows steadily, then continues on at 5.70 m/s.
What is her acceleration on the rough ice?
I dont want the answer, I just want to know how to solve it. Its been bugging me that I cant find the solution to this problem. I have tried different methods and none of the answers I got were correct.
2007-09-26 05:49:18 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Okay, nevermind. I just solved the problem! OMG, I thought I tried everything but I guess I did but made one tiny mistake which skewed my answer a little bit. But the problem has been solved.
2007-09-26 06:01:51 · update #1
use vf^2 = vi^2 + 2*a*delta(x)
solve for a
a = (vf^2 - vi^2)/(2*delta(x))
you know all of the varibles.
...
Ye this is the right way of solving it. But when I did it the first time, I got a different answer cuz I had a bit of math error in there that lead me to the wrong answer.
Then after I wrote this question here, I found a different answer when I did it on paper. Hehehe.
2007-09-26 08:13:52 · update #2
How do I choose someone's answer as the best answer?
2007-09-26 08:16:53 · update #3
use vf^2 = vi^2 + 2*a*delta(x)
solve for a
a = (vf^2 - vi^2)/(2*delta(x))
you know all of the varibles.
2007-09-26 06:22:34 · answer #1 · answered by civil_av8r 7 · 0⤊ 0⤋
In all honesty and fairness i think of bringing him ( my 2 month and 3 week old toddler boy) into the worldwide grow to be plenty extra good than elevating him so a techniques. he's an project-free going toddler. in basic terms "whines" while he's hungry or getting his diaper replaced. He has in basic terms cried actually two times because being in the worldwide. 1st time while he have been given his first photos and 2nd time in the motor vehicle twist of destiny we've been in. The no longer project-free section is being far flung from acquaintances and family contributors whom want to fulfill him (we are stationed foreign places). i might do something for my son. and could't think of my life without him. Its project-free being a parent. even nonetheless it has its extremely no longer project-free moments. a number of those moments make you want to cry.
2016-10-20 01:13:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(5.70 m/s - 8.40 m/s) / 4.80 m = 5.88 s.
The skater has decelerated:
-2.70 m/s velocity change over the rough ice in 5.88s.
Dividing the velocity change by the time taken should give you the answer.
Answer = (-2.70/5.88) m/s/s.
2007-09-26 06:23:11 · answer #3 · answered by BB 7 · 0⤊ 0⤋