Two forces F_1 and F_2, act at a point. F_1 has a magnitude of 9.00 and is directed at an angle of 63.0 degrees above the negative x axis in the second quadrant. F_2 has a magnitude of 5.20 and is directed at an angle of 53.7 degrees below the negative x axis in the third quadrant.
2007-09-26 05:47:18 · 1 answers · asked by bg 1 in Science & Mathematics ➔ Physics
vector f = mag(f) * (cos(theta),sin(theta)) when theta is CCW relative to +x axis.
f1 = (-4.085914D+000 +8.019059D+000)
f2 = (-3.078469D+000 -4.190827D+000)
ft = f1+f2 = (-7.164383D+000 +3.828232D+000)
Magnitude (ft) = 8.123038
Angle (CCW from +x) = arctan2(v3(2), v3(1)) = 151.8825 deg
arctan2(Vy, Vx) accommodates the full 360-deg range of angles whereas the normal arctan(Vy/Vx) function can only output angles in the +x half of the plane, -90 to 90 deg. In this case it's helpful since the problem was set up for a -x resultant.
2007-09-26 06:15:51 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋