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How far below an initial straight-line path will a projectile fall in one second? Is this depend on the angle of launch or on the initial speed of the projectile?

2007-09-26 05:45:46 · 3 answers · asked by Summer W 1 in Science & Mathematics Physics

3 answers

s = at^2/2 = 9.8/2 = 4.9 m
It's independent of initial conditions.
Of course the straight-line path depends on launch angle, but the distance below it doesn't. Gravity acts only along the y axis.

2007-09-26 06:05:33 · answer #1 · answered by kirchwey 7 · 0 0

9.8 meters or 32.2 feet. (assuming it is horizontal)

It does depend on the angle of launch and initial speed in the y direction (but not x).

2007-09-26 05:49:41 · answer #2 · answered by Anonymous · 0 0

BOTH ,THE SPEED AND THE ANGLE, 30DEG WILL GET THE FARTHER DISTANT .

2007-09-26 05:53:24 · answer #3 · answered by Anonymous · 0 0

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