tidal locking
2007-09-26 05:16:32
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answer #1
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answered by Anonymous
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An object, such as the moon (and the Earth) that rotates about its own axis but is also affected by external gravitational forces, tends to be slowed by that external gravitational force. It is called tidal braking and is the result of one side of the body being closer to the gravitational force than the other. Both bodies could be perfectly spherical and the mass evenly distributed and the tidal braking would still occur. Because the Earth/moon relationship is so close, the gravitational force of the Earth is much greater on the moon than that of the sun, thus the moon is locked to the Earth (in terms of rotation only), though it does have a little wobble to it that we know as libration.
Most moons become gravitationally locked to their planet in a fairly short time, but that doesn't mean that all moons are locked.
J.
http://www.jrichardjacobs.net
2007-09-26 05:41:36
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answer #2
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answered by orbitaldata 3
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The Moon revolves once around the Earth, in exactly the same time as it takes to rotate once around its own axis - approximately, 30 Earth days, which is equal to "one Moon day."
2007-09-26 05:21:18
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answer #3
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answered by Sam 7
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Period of rotation of the Moon about its axis and its revolution around the Earth are the same.
2007-09-26 05:15:02
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answer #4
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answered by ag_iitkgp 7
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It is caused because the moon is Tidal Locked to the earth.
2007-09-26 07:32:45
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answer #5
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answered by Mr. Smith 5
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It's called being tidally-locked.
The moon's center of mass is *not* at it's center, physically. It's center of mass is closer to Earth than the moon's center of volume.
2007-09-26 05:18:13
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answer #6
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answered by quantumclaustrophobe 7
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Both the period of rotation and the period of revolution are the same. As it is going around, it is turning at the same rate.
2007-09-26 05:17:33
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answer #7
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answered by thole pin 2
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I suppose the moon doesn't rotate , can't think of another reason.
2007-09-26 05:18:39
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answer #8
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answered by George D 2
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gravity.
2007-09-26 05:14:35
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answer #9
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answered by Anonymous
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