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Begin graphing f(x)=x^3 (I did) then use transformations of this graph to graph g(x)=-1/2x^3

2007-09-26 04:14:45 · 3 answers · asked by ChillChick 4 in Science & Mathematics Mathematics

How did the -1/2 become -2?

2007-09-26 07:58:27 · update #1

3 answers

y = -1/2x^3
so
-2y = x^3
so the - sign says to flip the graph upside down
and
the 2y means that intervals on y axis measure twice as long
so the curve will look half as tall in comparison

.

2007-09-26 04:23:28 · answer #1 · answered by The Wolf 6 · 1 0

I can't tell if this is a question...if you're asking how the graph would look, each y-value of 0.5x^3 will be half of what it was in the x^3 function, i.e. y(1) = 0.5*1, y(2) = 0.5*4, y(3) = 0.5*9, etc.

2007-09-26 04:20:56 · answer #2 · answered by Anonymous · 0 0

Just take the points (x, f(x)) that you calculated for y=f(x)=x^3 and write them as (x, f(x)/2) and you'll have all your 'new' points to plot.

Doug

2007-09-26 04:21:28 · answer #3 · answered by doug_donaghue 7 · 0 0

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