Write the ionic equation (help)?

Question

Write the ionic equation for the reaction, if any, between:

a)HNO3 and Na2CO3
b) NH3 and KCl

(please help me.. thank you!)

10 pts for the best answer(as always)

Answer 1

(a) Potential reaction:

2HNO3 + Na2CO3 --> H2CO3 + 2NaNO3

HNO3 = soluble, Na2CO3 = soluble, H2O = liquid, CO2 = gas, NaNO3 = soluble

There will be a reaction that produce water and CO2

So...

2H(+)aq + 2NO3(-)aq + 2Na(+)aq + CO3(2-)aq -->
H2O(liq) + 2NO3(-)aq + 2Na(+)aq + CO2(g)

Remove the common ions:

2H(+)aq + CO3(2-)aq --> H2O(liq) + CO2(g)

(b) NH3 + KCl --> KNH2 + HCl (potentially)

NH3(gas) + K(+)aq + Cl(-)aq -->
K(+)aq + NH2(-)aq + H(+)aq + Cl(-)aq

Since NH3 is a gas initially this will be a no reaction.

However, if you consider ammonia solution as ammonium hydroxide (NH3+H2O --> NH4OH)

NH4(+)aq + OH(-)aq + K(+)aq + Cl(-)aq -->
NH4(+)aq + OH(-)aq + K(+)aq + Cl(-)aq

Net ionic equation: N.R. You still get a no reaction

Hope this helps
Oz

Answer 2

a). 2HNO3 + Na2CO3 = 2NaNO3 + CO2 + H2O

b) NH3 + KCl
NH4+(aq) ammonia sol'n + KCl = NH4Cl + K+(aq)