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Question 1
There were six more women on a committee than men. The committee was made up of 30 people.How many women were on the committee?

Question 2
Three consecutive integers have the sum of 153.
What is the first integer?
A.) 50
B.) 51
C.) 52
D.) 49
Question 3
Five times the first of three consecutive even integers is fourteen more than three times the second.
What is the third integer?
A.) The third integer is 10
B.) The third integer is 12
C.) The third integer is 14
D.) The third integer is 8
Question 4
The sum of three consecutive even integers is fifty four.
What is the second integer?
A.) 16
B.) 18
C.) 20
D.) 14
Question 5
An airplane flies at a rate of 356 km/h. The plane travels a total distance of 1424 km.
(Use Distance = Rate * Time for your equation.)
What is the time for this problem?
**please write your time as a number only**

2007-09-26 02:38:45 · 8 answers · asked by Joycelyn C 1 in Science & Mathematics Mathematics

8 answers

Question 1
women = x
men = x - 6

x + (x - 6) = 30
2x - 6 = 30
2x = 36
x = 18

Question 2
Integer 1 = x
Integer 2 = x + 1
Integer 3 = x + 2

x + (x + 1) + (x + 2) = 153
3x + 3 = 153
3x = 150
x = 50

Question 3
Integer 1 = x - 4
Integer 2 = x - 2
Integer 3 = x

5(x - 4) = 14 + 3(x - 2)
5x - 20 = 14 + 3x - 6
5x - 20 = 8 + 3x
2x - 20 = 8
2x = 28
x = 14

Question 4
Integer 1 = x - 2
Integer 2 = x
Integer 3 = x + 2

(x - 2) + x + (x + 2) = 54
3x = 54
x = 18

Question 5
356 * t = 1424
t = 1424 / 356 = 4

2007-09-26 02:46:51 · answer #1 · answered by Mathematica 7 · 2 0

1. x=man
x+6=woman
2x+6=30
2x=30-6
=24
x=12
woman= 12+6
=18

2. x+(x+1)+(x+2)=153
3x+3=153
3x=153-3
=150
x=50

3. x, x+2, .x+4
3(x+2)=y
5x=14+y
5x=14+3x+6
5x-3x=14+6
2x=20
x=10
third=x+4
=10+4
=14

4. x+(x+2)+(x+4)=54
3x+6=54
3x=54-6
=48
x=16
second=16+2
=18

5. Distance = Rate * Time
1424=356*t
t=1424/356
=4 hours

2007-09-26 03:12:25 · answer #2 · answered by kid of phantom thief 1 · 0 0

Q1,...
let x = number of males
x+6= number of females

x + x +6 = 30
2x = 30-6
2x= 24
x=12

Q2,...
x = 1st
x+1=2nd
x+2=3rd

x + x+1 + x+2 = 153
3x+3 = 153
3x = 150
x = 50

Q3,....
5 (x) = 3(x+2) +14
5x = 3x + 20
5x-3x = 20
2x = 20
x=10

Q4,....
(x) + (x+2) + (x+4) = 54
3x + 6 =54
3x = 48
x = 16
2nd-----
x+2 = 16+2 = 18
Q5,.....
1424 = 356 km/hr * time
time = 4 hrs

2007-09-26 02:54:21 · answer #3 · answered by xleryy 2 · 0 0

Question 1:
Number of women=x
Number of men =x-6
total number =30
30=x+x-6
2x=30+6
x=36/2
x=18 women
x-6=12 men

Question2:
n=1st number
n+1=2nd number
n+2=3rd number
sum = 153
n+n+1+n+2= 153
3n+3=153
3n=153-3=150
n=50

Question 3:
n=1st number
n+2=2nd number
n+4=3rd number
5n=3(n+2)+14
5n=3n+6+14
2n=20
n=10
n+4=14 = third number

question 4:
n +(n+2) +(n+4) = 54
3n+6=54
3n=54-6=48
n=16
n+2 =18 = second number

Question5:
D=r*t
1424=356t
t=1424/356
t=4

2007-09-26 03:01:15 · answer #4 · answered by bignose68 4 · 0 0

Let

x = men

x + 6 = women

30 = total men and women

- - - - -

The equation

x + x + 6 = 30

Collect like terms

2x + 6 = 30

Transpose 6

2x + 6 - 6 = 30 - 6

Collect like terms

2x = 24

Divide both sides of the equation by 2

2x / 2 = 24 / 2

x = 24 / 2

x = 12. . .←. .men

- - - - - -


Women = w + 6

12 + 6 = 18

There are 18 women

There are 12 men

- - - - - - - -s-

2007-09-26 02:53:53 · answer #5 · answered by SAMUEL D 7 · 0 0

1. x=number of men
x+x+6=30
2x=30-6
2x=24x=12 men, 18 women.

2. x= first integer in series
x+x+1+x+2=153
3x=3=153
3x=150
x=50
integers are 50, 51 and 52

3. first integer is x, second integer is x+2, thrid is x+4
5x=3(x+2)+14
5x=3x+6+14
5x=3x+20
2x=20
x=10
third integer is 14

4. x=first int.
x+x+2+x+4=54
3x+6=54
3x=48
x=16
2nd integer is 18

5.1424=356x
x=4 hours
x=16

2007-09-26 02:49:57 · answer #6 · answered by alb_4 3 · 0 0

For increasing cubic binomials the final formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D

2016-10-20 00:51:31 · answer #7 · answered by ? 4 · 0 0

Is this an exam?

2007-09-26 02:44:59 · answer #8 · answered by Anonymous · 0 1

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