The answer is 1:1:2.
The simple logic also gives answer.
The result must give 15; that is higher than first two rates, hence sugar of the last rate should be given more weight.
2007-09-29 04:30:43
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answer #1
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answered by Anonymous
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several such proportions are possible.
for example when all the three type of sugar are mixed together (each 1Kg)in equal proportion it makes Rs 14 /kg
ie. (11+13+18)/3 = 14
there are several ways to make numerator equal to 45 and get 15
for instance (5+13+27)=45 then 45/3=15
ie. 1/2:1:3/2 or 1:2:3
2007-09-28 11:08:26
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answer #2
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answered by shasti 3
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Let x kg of Rs. 11, y kg of Rs. 13 and z kg of Rs 18 are mixed.
Total sugar sold = (x+y+z) kg sold at Rs. 15
Therefore,
x à 11 + y Ã13 + z Ã18 = (x+y+z) à 15
11x + 13y + 18z = 15x +15y +15 z
3 z = 4 x + 2 y
Therefore x = 1, y =1 and z = 2
Proportion is 1 : 1 : 2
2007-09-26 09:47:23
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answer #3
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answered by Pranil 7
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The 11 Rs/Kg sugar, 13Rs/Kg sugar and 18Rs/Kg sugar should be mixed in the ratio of 1:1:2 and the cost of the resultant mix will be 15 Rs/kg.
2007-09-26 08:40:09
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answer #4
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answered by Anonymous
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1:1:2
2007-09-27 05:09:05
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answer #5
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answered by shailesh 2
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11*15 =165
13*15 =195
18*15 =270
42 Total =630
630/42= 15
2007-09-26 08:32:44
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answer #6
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answered by charlatan 7
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one condition must be given
the proportion of Rs11 and Rs13
2007-09-26 08:22:45
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answer #7
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answered by CPUcate 6
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Go to a library and look up a chapter on ratio and the prepositions, in an algebra book. If it is not in your algebra book. Try your book first.
2007-09-26 09:18:57
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answer #8
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answered by minootoo 7
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