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Above question related to mixture and allegation

2007-09-26 01:16:40 · 8 answers · asked by sakira 1 in Science & Mathematics Mathematics

8 answers

The answer is 1:1:2.
The simple logic also gives answer.
The result must give 15; that is higher than first two rates, hence sugar of the last rate should be given more weight.

2007-09-29 04:30:43 · answer #1 · answered by Anonymous · 0 1

several such proportions are possible.
for example when all the three type of sugar are mixed together (each 1Kg)in equal proportion it makes Rs 14 /kg
ie. (11+13+18)/3 = 14
there are several ways to make numerator equal to 45 and get 15
for instance (5+13+27)=45 then 45/3=15
ie. 1/2:1:3/2 or 1:2:3

2007-09-28 11:08:26 · answer #2 · answered by shasti 3 · 0 0

Let x kg of Rs. 11, y kg of Rs. 13 and z kg of Rs 18 are mixed.
Total sugar sold = (x+y+z) kg sold at Rs. 15
Therefore,
x × 11 + y ×13 + z ×18 = (x+y+z) × 15
11x + 13y + 18z = 15x +15y +15 z
3 z = 4 x + 2 y
Therefore x = 1, y =1 and z = 2
Proportion is 1 : 1 : 2

2007-09-26 09:47:23 · answer #3 · answered by Pranil 7 · 0 0

The 11 Rs/Kg sugar, 13Rs/Kg sugar and 18Rs/Kg sugar should be mixed in the ratio of 1:1:2 and the cost of the resultant mix will be 15 Rs/kg.

2007-09-26 08:40:09 · answer #4 · answered by Anonymous · 0 0

1:1:2

2007-09-27 05:09:05 · answer #5 · answered by shailesh 2 · 0 0

11*15 =165
13*15 =195
18*15 =270

42 Total =630

630/42= 15

2007-09-26 08:32:44 · answer #6 · answered by charlatan 7 · 0 0

one condition must be given
the proportion of Rs11 and Rs13

2007-09-26 08:22:45 · answer #7 · answered by CPUcate 6 · 0 0

Go to a library and look up a chapter on ratio and the prepositions, in an algebra book. If it is not in your algebra book. Try your book first.

2007-09-26 09:18:57 · answer #8 · answered by minootoo 7 · 0 2

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