a. (64/27)^-1/3 X 125^2/3
b. if 6x=5^1000 , find x
2007-09-24 21:08:15 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(64/27)^(-1/3) × 125^(2/3)
= (4^3 / 3^3)^(-1/3) × (5^3)^(2/3)
= (3/4) × 5^2
= 75/4.
6x = 5^1000
so x = (5^1000) / 6 ≈ 1.56×10^698, so I wouldn't bother trying to write it out in full.
2007-09-24 21:23:25 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
a.
(64/27)^-1/3 X 125^2/3
1/(64/27)^1/3 X [{125}^1/3]^2
The above means " take the cube root of 1/(64/27) and multiply it by the cube root of 125 squared"
1/(4/3) X 5^2
3/4 X 25
75/4
b.
6x= 5^1000
x=5^1000/6
2007-09-25 04:36:05 · answer #2 · answered by Grampedo 7 · 0⤊ 0⤋
1. (64/27)^-1/3 x (125)^2/3
look for the common power of the figure in the bracket
64=4^3; 27=3^3:; 125=5^3
insert them accordingly into each bracket
(4^3/3^3)^-1/3 x (5^3)^2/3
regroup
(4/3)^3(-1/3) x (5)^3(2/3)
=(4/3)^-1 x(5)^2
=3/4 x 25
=75/4
into mixed fraction=18 3/4
2.
2007-09-25 07:21:20 · answer #3 · answered by prinsex prex 2 · 0⤊ 0⤋
a.
=4/3 x 25
=100/3
b. sorry no calculator
x=5^1000/6
2007-09-25 04:34:28 · answer #4 · answered by rekam noinipo 1 · 0⤊ 0⤋
the answer for B-the x is right near the 6
2007-09-25 04:15:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
a. Answer is 18.75
b. x would be equal to five to the power of a thousand divided by 6
2007-09-25 04:28:33 · answer #6 · answered by Harsh Saini 2 · 0⤊ 0⤋
check this www.mathguru.com n get ur problem soved
2007-09-25 04:49:16 · answer #7 · answered by ishita 1 · 0⤊ 0⤋