Please simplify?

0 ⤊

a . log₂ 5 + 3 log₃ x=3

b. If x=2y-4 and y = 7s + 1, express s in term of x

2007-09-24 20:51:37 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

log 5+log x^3=3
log 5x^3=3
10^3=5x^3
200=x^3
x=200^1/3

x+4=2y
x/2+2=y
x/2+2=7s+1
x/2+1=7s
x/14+1/7=s

2007-09-24 21:01:01 · answer #1 · answered by chasrmck 6 · 0⤊ 0⤋

log₂ 5 + 3 log₃x = 3
log₃x = [3 - log₂5] / 3
log₃x = [3 - log₂5] / 3
to find
log₂5 = z
2^z =5
z log 2 = log 5
z = log5 / log2 = 2.322
log₃x = 0.226
So:
x = 3 ^(0.226)
x = 1.281

Given
x=2y-4
y = 7s + 1
Plug Eq 2 into Eq 1
x = 2( 7s + 1 ) - 4
x = 14s +2 -4
x = 14s -2
14s = x+2
s = (x+2)/14

2007-09-25 04:17:13 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋

10sy=x

2007-09-25 04:00:59 · answer #3 · answered by wes m 2 · 0⤊ 1⤋