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Does the integral from 4 to infinity of (3+sinx)/x diverge?
I need to use a direct comparsion test to figure this out but I dont know what to comapre it to.
any help is much appreciated

2007-09-24 19:25:35 · 3 answers · asked by starz8 2 in Science & Mathematics Mathematics

3 answers

It certainly does. Note that 3 + sin x is between 2 and 4, so for all x > 0 we have
(3 + sin x) / x ≥ 2 / x > 0
and we know the integral to ∞ of 2/x diverges.

2007-09-24 19:28:53 · answer #1 · answered by Scarlet Manuka 7 · 0 0

Separate it into two integrals: 3/x and sinx / x.

In order for the total integral to be divergent at least one of the those individual terms has to be divergent.

2007-09-24 19:33:54 · answer #2 · answered by Anonymous · 0 0

Yes it is simple. Compare it to 1/x.
3+sinx >= 3 -1 since since sinx is >= -1 Therefore
(3 + sinx)/x >= 2/x > 1x. Therefore since the integral of 1/x is divergent the integral of the term is divergent.

2007-09-24 19:39:15 · answer #3 · answered by ? 5 · 1 0

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