I cant figure it out....
2007-09-24 17:14:51 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
What are the 4 integers please put them down...
2007-09-24 17:17:54 · update #1
THank you so much!
2007-09-24 17:20:07 · update #2
47+49+51+53=200
2007-09-24 17:19:25 · answer #1 · answered by Cabt.man 1 · 3⤊ 0⤋
4 consecutive odd integers means:
x, x+2, x+4, and x+6, assuming x is odd
The sum is 200, so:
x + (x+2) + (x+4) + (x+6) = 200
4x + 12 = 200
4x = 188
x = 46
Wait a minute -- are you sure you have the problem correct?
2007-09-25 00:21:25 · answer #2 · answered by Bat Boy Jr 2 · 0⤊ 0⤋
x + x + 2 + x = 4 + x + 6 = 200
4x + 12 = 200
4x = 188
x = 47
47, 49, 51, 53
2007-09-25 00:20:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Hi Jj,
let's say the four integers are:
X
X + 2
X + 4
X + 6
X + (X + 2) + (X + 4) + (X+6) = 200
4X + 12 = 200
4X = 188
X = 47
So, your numbers are:
47, 49, 51, 53
hth.
REgards,
Chas.
2007-09-25 00:20:12 · answer #4 · answered by Chas. 3 · 0⤊ 0⤋
47, 49, 51, 53
2007-09-25 00:23:21 · answer #5 · answered by Rochesmk 1 · 0⤊ 0⤋
let x=first odd integer
x+2=2nd odd integer
x+4=3rd odd integer
x+6=4th odd integer
x+x+2+x+4+x+6=200
4x=200-12
4x=188
x=47
x+2=49
x+4=51
x+6=53
2007-09-25 00:22:41 · answer #6 · answered by ptolemy862000 4 · 0⤊ 0⤋
OK
N + (N + 2) + (N + 4) + (N + 6) = 200
4N + 12 = 200
4N = 188
N = 47
Numbers are { 47, 49, 51, 53}
2007-09-25 00:16:59 · answer #7 · answered by Mαtt 6 · 0⤊ 2⤋
(2n + 1) + (2n + 3) + (2n + 5) + (2n + 7) = 200
8n + 16 = 200
8n = 184
n = 23
Numbers are 47 , 49 , 51 , 53
2007-09-25 13:34:00 · answer #8 · answered by Como 7 · 0⤊ 0⤋
Confirmed, above answers are correct.
2007-09-25 00:21:15 · answer #9 · answered by X6B7A 2 · 0⤊ 1⤋