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An object mass m dropped from a height h is moving at a velocity v just before ot hits the ground. If the acceleration of gravity is g, the average friction force acting on the object is...

Note: the answer is (2mgh-mv^2)/2h. I just need to know how to get there :-]]

2007-09-24 17:01:48 · 1 answers · asked by heyy ya 1 in Science & Mathematics Physics

1 answers

From energy considerations.
Please note that the potential energy before the drop of this object: mgh
After drop but right before the object touches the ground: 0.5mv^2
The lose of the energy is due to friction force F through this fall (distance h), and the work done by this force is Fh:
Fh = mgh - 0.5mv^2
You get the result after rearrange this equation.

2007-09-26 09:34:40 · answer #1 · answered by Hahaha 7 · 0 0

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